QJEEM21Chced4: JEE Main 2021 Chemistry - Class 12 JEEM21Chced4 Solution: A KCl solution of conductivity 0.14 S m − 1 shows a resistance…

Question

Verified Solution • 2025–26 Session moderate

A KCl solution of conductivity 0.14 S m^{$-$ 1} shows a resistance of 4.19

Ω

in a conductivity cell. If the same cell is filled with an HCl solution, the resistance drops to 1.03

Ω

. The conductivity of the HCl solution is ____________

\times

10^{$-$ 2} S m^{$-$ 1}. (Round off to the Nearest Integer).

Accepted Answer

For KCl solution,

R = (\frac{1}{K}) (\frac{l}{A}) \Rightarrow \frac{l}{A} = R \times K = 4.19 \times 0.14

= 0.58

For HCl solution,

R = (\frac{1}{K}) (\frac{l}{A})

\Rightarrow K = \frac{(l / A)}{R} = \frac{0.58}{1.03} = 0.56 = 56 \times 10^{- 2}

Sm^{$-$ 1}

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