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QJEEM21Chcdea: JEE Main 2021 Chemistry - Class 11 JEEM21Chcdea Solution: 3.12 g of oxygen is adsorbed on 1.2 g of platinum metal. The…

3.12 g of oxygen is adsorbed on 1.2 g of platinum metal. The volume of oxygen adsorbed per gram of the adsorbent at 1 atm and 300 K in L is __________.

[R = 0.0821 L atm K −- 1mol −- 1]

Step-by-Step Verified Solution

Moles of O2 = 3.1232{{3.12} \over {32}} = 0.0975

Using ideal gas equation : PV = nRT

V = 0.0975×0.082×3001{{0.0975 \times 0.082 \times 300} \over 1} = 2.4 L

∴\therefore Volume of O2(g) adsorbed per gram of the

adsorbent = 2.41.2{{2.4} \over {1.2}} = 2

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