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QJEEM21Chbf91: JEE Main 2021 Chemistry - Class 11 JEEM21Chbf91 Solution: A 3 B 2 is a sparingly soluble salt of molar mass M (g mol 1 )…

A3B2 is a sparingly soluble salt of molar mass M (g mol −- 1) and solubility x g L −- 1. The solubility product satisfies Ksp=a(xM)5{K_{sp}} = a{\left( {{x \over M}} \right)^5} . The value of a is _____________. (Integer answer)

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JEE Main 2021 (Online) 31st August Morning Shift Chemistry - Ionic Equilibrium Question 52 English Explanation

KSP = (3s)3 (2s)2

KSP = 108 s5 & s = (x/M)

KSP = 108 (xM)5{\left( {{x \over M}} \right)^5}

given Ksp=a(xM)5{K_{sp}} = a{\left( {{x \over M}} \right)^5}

comparing a = 108

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