QJEEM21Cha8d0: JEE Main 2021 Chemistry - Class 11 JEEM21Cha8d0 Solution: The number of atoms in 8g of sodium is x 10 23 . The value of x …

Question

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The number of atoms in 8g of sodium is x

\times

10²³. The value of x is ____________. (Nearest integer)

[Given : N_A = 6.02

\times

10²³ mol^{$-$ 1}

Atomic mass of Na = 23.0 u]

Accepted Answer

Given, mass of Na = 8g

Molar mass of Na = 23 gmol^{$-$ 1}

{{Weight\,of\,sodium\,atom} \over {Molecular\,mass\,of\,sodium\,atom}} = {{Number\,of\,atoms} \over {Avogadro's\,number}}

{{8g} \over {23g}} = {{Number\,of\,atoms} \over {6.022 \times {{10}^{23}}}}

Number of atoms

= {{8 \times 6.022} \over {23}} \times {10^{23}}

Number of atoms = 2.09

\times

10²³

x

\approx

2

Hence, answer is 2.

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