Verified Solution • 2025–26 Session moderate

QJEEM21Cha19f: JEE Main 2021 Chemistry - Class 11 JEEM21Cha19f Solution: Complete combustion of 3g of ethane gives x × 10 22 molecules…

Complete combustion of 3g of ethane gives x × 1022 molecules of water. The value of x is __________. (Round off to the Nearest Integer). [Use : NA = 6.023 × 1023; Atomic masses in u : C : 12.0; O : 16.0; H : 1.0]

Step-by-Step Verified Solution

C2H6+72O2⟶2CO2+3H2O

Here, C2H6=3gm=330=0.1 mol

From 1 mol C2H6 we get 3 mol H2O

∴ From 0.1 mol C2H6 we get = 3 × 0.1 mol H2O

∴ Moles of H2O = 0.3

= 0.3 × 6.023 × 1023 molecules

= 1.8069 × 1023 molecules

= 18.069 × 1022 molecules

Related Learning Resources & Exam Preparation