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QJEEM21Cha0ca: JEE Main 2021 Chemistry - Class 11 JEEM21Cha0ca Solution: An aqueous KCl solution of density 1.20 g mL 1 has a molality…

An aqueous KCl solution of density 1.20 g mL −- 1 has a molality of 3.30 mol kg −- 1. The molarity of the solution in mol L −- 1 is ____________ (Nearest integer) [Molar mass of KCl = 74.5]

Step-by-Step Verified Solution

1000 kg solvent has 3.3 moles of KCl

1000 kg solvent →\to 3.3 ×\times 74.5 gm KCl →\to 245.85

Weight of solution = 1245.85 gm

Volume of solution = 1245.851.2{{1245.85} \over {1.2}} ml

So molarity = 3.3×1.21245.85×1000=3.17{{3.3 \times 1.2} \over {1245.85}} \times 1000 = 3.17

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