Verified Solution • 2025–26 Session moderate

QJEEM21Ch9b34: JEE Main 2021 Chemistry - Class 11 JEEM21Ch9b34 Solution: At 1990 K and 1 atm pressure, there are equal number of Cl 2 ,…

At 1990 K and 1 atm pressure, there are equal number of Cl2, molecules and Cl atoms in the reaction mixture. The value of Kp for the reaction Cl2 (g) ⇌\rightleftharpoons 2Cl(g) under the above conditions is x ×\times 10-1.
The value of x is _______. (Rounded off to the nearest integer)

Step-by-Step Verified Solution

Cl2(g) ⇌\rightleftharpoons 2Cl(g)

Let moles of both of Cl2 and Cl molecule be x.

Partial pressure of Cl is, pCl=x2x×1=12{p_{Cl}} = {x \over {2x}} \times 1 = {1 \over 2}

Partial pressure of Cl2 is, pCl2=x2x×1=12{p_{C{l_2}}} = {x \over {2x}} \times 1 = {1 \over 2}

Now, Kp=(pCl)2pCl2{K_p} = {{{{({p_{Cl}})}^2}} \over {{p_{C{l_2}}}}}

⇒Kp=(1/2)21/2=12=0.5\Rightarrow {K_p} = {{{{(1/2)}^2}} \over {1/2}} = {1 \over 2} = 0.5

= 5 ×\times 10 −- 1

Hence, x ×\times 10 −- 1

x = 5

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