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QJEEM21Ch8ff7: JEE Main 2021 Chemistry - Class 11 JEEM21Ch8ff7 Solution: In basic medium oxidises to form and itself changes into . The…

In basic medium CrO42−Cr{O_4}^{2 - } oxidises S2O32−{S_2}{O_3}^{2 - } to form SO42−S{O_4}^{2 - } and itself changes into Cr(OH)4−Cr{(OH)_4}^ - . The volume of 0.154 M CrO42−Cr{O_4}^{2 - } required to react with 40 mL of 0.25 M S2O32−{S_2}{O_3}^{2 - } is __________ mL. (Rounded off to the nearest integer)

Step-by-Step Verified Solution

17H2O+8CrO4+3S2O3⟶6SO4+8Cr(OH)4−+2OH−

Applying mole-mole analysis

0.154×v8=40×0.253{{0.154 \times v} \over 8} = {{40 \times 0.25} \over 3}

v = 173 mL

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