QJEEM21Ch8f1c: JEE Main 2021 Chemistry - Class 11 JEEM21Ch8f1c Solution: The volume occupied by 4.75 g of acetylene gas at 50 C and 740…

Given, mass of C₂H₂(g) = 4.75 g

Molecular weight = 26 g/mol

Temperature = 50 + 273 = 323 K

Pressure = 740 torr/mm of Hg

Pressure = ${{740} \over {760}}$ atm

R = 0.0821 L atm mol ^{$-$ 1} K ^{$-$ 1}

Hence, no. of mole n = ${{4.75} \over {26}}$ mol

Formula used, pV = nRT (ideal gas)

$\Rightarrow V = {{nRT} \over p} = {{4.75} \over {26}} \times {{0.0821 \times 323} \over {(740/760)}}$

$= {{96314.078} \over {19240}} = 5.0059$ L = 5 L