QJEEM21Ch886e: JEE Main 2021 Chemistry - Class 11 JEEM21Ch886e Solution: The molarity of the solution prepared by dissolving 6.3 g of…

Question

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The molarity of the solution prepared by dissolving 6.3 g of oxalic acid (H₂C₂O₄.2H₂O) in 250 mL of water in mol L^{$-$ 1} is x

\times

10^{$-$ 2}. The value of x is _____________. (Nearest integer) [Atomic mass : H : 1.0, C : 12.0, O : 16.0]

Accepted Answer

[H_{2} C_{2} O_{4} .2 H_{2} O] = \frac{w e i g h t / M_{w}}{V (L)}

\Rightarrow x \times 10^{- 2} = \frac{6.3 / 126}{250 / 1000}

x = 20

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