Verified Solution • 2025–26 Session moderate

QJEEM21Ch8278: JEE Main 2021 Chemistry - Class 12 JEEM21Ch8278 Solution: The total number of unpaired electrons present in [Co(NH 3 ) 6…

The total number of unpaired electrons present in [Co(NH3)6]Cl2 and [Co(NH3)6]Cl3 is :

Step-by-Step Verified Solution

[Co(NH3)6]Cl2

Co2+ : [Ar]3d74s04p0

For this complex Δ\Delta 0 < P.E., so pairing of electron does not take place.

sp3d2 hybridisation

Total 3 unpaired electrons are present.

[Co(NH3)6]Cl3

Co3+ : [Ar]3d6 4s0 4p0

d2sp3 hybridistion

NH3 acts as SFL because Δ\Delta 0 > P.E.

So, here all electrons becomes paired.

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring