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QJEEM21Ch808f: JEE Main 2021 Chemistry - Class 12 JEEM21Ch808f Solution: When 10 mL of an aqueous solution of Fe 2+ ions was titrated in …

When 10 mL of an aqueous solution of Fe2+ ions was titrated in the presence of dil H2SO4 using diphenylamine indicator, 15 mL of 0.02 M solution of K2Cr2O7 was required to get the end point. The molarity of the solution containing Fe2+ ions is x × 10−2 M. The value of x is __________. (Nearest integer)

Step-by-Step Verified Solution

milli-equivalents of Fe2+ = milli-equivalents of K2Cr2O7

M × 10 × 1 = 0.02 × 15 × 6

⇒ M = 0.18 = 18 × 10−2 M

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