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QJEEM21Ch7faf: JEE Main 2021 Chemistry - Class 11 JEEM21Ch7faf Solution: Using the provided information in the following paper…

Using the provided information in the following paper chromatogram :

JEE Main 2021 (Online) 25th February Morning Shift Chemistry - Basics of Organic Chemistry Question 160 English
Fig : Paper chromatography for compounds A and B.

the calculated Rf value of A ________ ×\times 10-1.

Step-by-Step Verified Solution

Rf=Distan⁡ce travelled by compoundDistan⁡ce travelled by solvent{R_f} = {{Dis\tan ce\,travelled\,by\,compound} \over {Dis\tan ce\,travelled\,by\,solvent}}

On chromatogram distance travelled by compound is = 2 cm

Distance travelled by solvent = 5 cm

So, Rf=25={R_f} = {2 \over 5} = 4 ×\times 10 −- 1 = 0.4

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