Verified Solution • 2025–26 Session moderate

QJEEM21Ch7d91: JEE Main 2021 Chemistry - Class 12 JEEM21Ch7d91 Solution: The major product formed in the following reaction is :

The major product formed in the following reaction is :

JEE Main 2021 (Online) 26th August Morning Shift Chemistry - Haloalkanes and Haloarenes Question 82 English

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/2c72f5863fcc8738fd78fc55d7e170510e19368a81f479477313da5f00bc14c1.webp
  • B https://ik.imagekit.io/novatra/photos/9369cd8e1ce1425469d44837f571cea14d0766e95ac0ce27872b35e8f2a801e2.webp
  • C https://ik.imagekit.io/novatra/photos/39a2d452e61bf2360ea6a5bcfa8296a18137ebaab7a7318aa2467a2e6126e821.webp
  • D https://ik.imagekit.io/novatra/photos/8fc56e78de045a45315a062d7ea501eef31641c19dea069c2e42ac1dbebc844c.webp

Step-by-Step Verified Solution

JEE Main 2021 (Online) 26th August Morning Shift Chemistry - Haloalkanes and Haloarenes Question 82 English Explanation 1

This addition is known as 1, 4-addition.

Mechanism This reaction can undergoes two pathways

JEE Main 2021 (Online) 26th August Morning Shift Chemistry - Haloalkanes and Haloarenes Question 82 English Explanation 2

Out of the two intermediates formed in two paths, the path B intermediate is more stable as it has more stable carbocation. So, a major product will be formed because of path B.

JEE Main 2021 (Online) 26th August Morning Shift Chemistry - Haloalkanes and Haloarenes Question 82 English Explanation 3
1, 2-addition product is formed at low temperature and will be less stable as the double bond is less substituted. 1, 4-addition is a thermodynamically stable product as the double bond is more substituted. As diene is in excess and HBr is limited in reaction, so diene cannot be formed. So option (b) is incorrect.

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