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QJEEM21Ch7cb3: JEE Main 2021 Chemistry - Class 11 JEEM21Ch7cb3 Solution: The transformation occurring in Duma's method is given below :…

The transformation occurring in Duma's method is given below :

C2H7N+(2x+y2)CuO→xCO2+y2H2O+z2N2+(2x+y2)Cu{C_2}{H_7}N + \left( {2x + {y \over 2}} \right)CuO \to xC{O_2} + {y \over 2}{H_2}O + {z \over 2}{N_2} + \left( {2x + {y \over 2}} \right)Cu

The value of y is ______________. (Integer answer)

Step-by-Step Verified Solution

C2H7N+(2x+y2)CuO→xCO2+y2H2O+z2N2+(2x+y2)Cu{C_2}{H_7}N + \left( {2x + {y \over 2}} \right)CuO \to xC{O_2} + {y \over 2}{H_2}O + {z \over 2}{N_2} + \left( {2x + {y \over 2}} \right)Cu

On balancing

C2H7N+152CuO→2CO2+72H2O+12N2+152Cu{C_2}{H_7}N + {{15} \over 2}CuO \to 2C{O_2} + {7 \over 2}{H_2}O + {1 \over 2}{N_2} + {{15} \over 2}Cu

On comparing

y = 7

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