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QJEEM21Ch7aec: JEE Main 2021 Chemistry - Class 11 JEEM21Ch7aec Solution: An average person needs about 10000 kJ energy per day. The…

An average person needs about 10000 kJ energy per day. The amount of glucose (molar mass = 180.0 g mol −- 1) needed to meet this energy requirement is ____________ g.

(Use : Δ\Delta CH(glucose) = −- 2700 kJ mol −- 1)

Step-by-Step Verified Solution

1 mole glucose give 2700 kJ energy,

so mole of glucose needed for 104 kJ energy

= 100002700=3.703{{10000} \over {2700}} = 3.703 moles

Weight of glucose = 3.703 ×\times 180 g/moles

= 666.666

≈\approx 667 g

Hence, amount of glucose required is 667 g.

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