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QJEEM21Ch74a0: JEE Main 2021 Chemistry - Class 12 JEEM21Ch74a0 Solution: The total number of unpaired electrons present in the complex K …

The total number of unpaired electrons present in the complex K3[Cr(oxalate)3] is _____________.

Step-by-Step Verified Solution

In K3[Cr(C2O4)]{K_3}\left[ {Cr\left( {{C_2}{O_4}} \right)} \right] , oxidation number of Cr :

3(+1)+x+3(−2)=03( + 1) + x + 3( - 2) = 0

⇒x=+3\Rightarrow x = + 3

∴\therefore 24Cr+3=[Ar]3d3{}_{24}C{r^{ + 3}} = \left[ {Ar} \right]3{d^3}

∴\therefore Number of unpaired electrons = 3

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