Verified Solution • 2025–26 Session moderate

QJEEM21Ch7355: JEE Main 2021 Chemistry - Class 12 JEEM21Ch7355 Solution: If the activation energy of a reaction is 80.9 kJ mol 1 , the…

If the activation energy of a reaction is 80.9 kJ mol −- 1, the fraction of molecules at 700 K, having enough energy to react to form
products is e −- x. The value of x is __________. (Rounded off to the nearest integer) [Use R = 8.31 J K −- 1 mol −- 1]

Step-by-Step Verified Solution

Ea = 80.9 kJ/mol

Fraction of molecules able to cross energy barrier = e −- Ea/RT = e −- x

x = EaRT=80.9×10008.31×700=13.91{{{E_a}} \over {RT}} = {{80.9 \times 1000} \over {8.31 \times 700}} = 13.91

⇒\Rightarrow x ≃\simeq 14

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