QJEEM21Ch65b2: JEE Main 2021 Chemistry - Class 12 JEEM21Ch65b2 Solution: Compound(s) which will liberate carbon dioxide with sodium…

The reactions of given compound with sodium bicarbonate solution are as follows


$\text { As } \mathrm{H}_2 \mathrm{CO}_3 \text { is weak acid it dissociate to liberate } \mathrm{CO}_2 \text { gas and } \mathrm{H}_2 \mathrm{O} \text {. }$


Equilibrium favours forward direction and $\mathrm{CO}_2$ is liberated. In the above two reactions, $\mathrm{H}_2 \mathrm{CO}_3$ is comparatively weak acid.

$\therefore \mathrm{CO}_2$ gas is liberated.


Equilibrium favours backward direction and $\mathrm{CO}_2$ is not liberated.

Thus, only $B$ and $C$ will liberate carbon dioxide with sodium bicarbonate solution.