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QJEEM21Ch630f: JEE Main 2021 Chemistry - Class 12 JEEM21Ch630f Solution: C 6 H 6 freezes at 5.5 C. The temperature at which a solution…

C6H6 freezes at 5.5 ∘^\circ C. The temperature at which a solution of 10g of C4H10 in 200g of C6H6 freeze is __________ ∘^\circ C. (The molal freezing point depression constant of C6H6 is 5.12 ∘^\circ C/m.)

Step-by-Step Verified Solution

Pure solvent : C6H6(l)

Given,

Tfo=5.5∘CT_f^o = 5.5^\circ C

Kf=5.12∘C/m⇒m=200g{K_f} = 5.12^\circ C/m \Rightarrow m = 200g

msolute=10g{m_{solute}} = 10g

Molar mass of solute C4H10=12×4+10=58{C_4}{H_{10}} = 12 \times 4 + 10 = 58

Solute (C4H10) is non-dissociative;

∴\therefore i = 1

∴\therefore ΔTf=iKf m\Delta {T_f} = i{K_f}\,m

⇒(Tfo−Tf1)=1×5.12×(10/58)(200/1000)\Rightarrow (T_f^o - T_f^1) = 1 \times 5.12 \times {{(10/58)} \over {(200/1000)}}

5.5−Tf1=5.12×5×1058⇒Tf1=1.086∘C5.5 - T_f^1 = {{5.12 \times 5 \times 10} \over {58}} \Rightarrow T_f^1 = 1.086^\circ C

or Tf1≈1∘CT_f^1 \approx 1^\circ C

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