QJEEM21Ch62b2: JEE Main 2021 Chemistry - Class 11 JEEM21Ch62b2 Solution: Two salts A 2 X and MX have the same value of solubility…

Question

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Two salts A₂X and MX have the same value of solubility product of 4.0

\times

10^{$-$ 12}. The ratio of their molar solubilities i.e.

{{S({A_2}X)} \over {S(MX)}}

= __________. (Round off to the Nearest Integer)

Accepted Answer

For A₂X

\begin{matrix} A_{2} X & \to & 2 A^{+} & X^{2 -} \\ 2 S_{1} & S_{1} \end{matrix}

{K_{sp}} = 4S_1^3 = 4 \times {10^{ - 12}}

S₁ = 10^{$-$ 4}

for MX

\begin{matrix} M X & \to & M^{+} & X^{-} \\ S_{2} & S_{2} \end{matrix}

{K_{sp}} = S_2^2 = 4 \times {10^{ - 12}}

S₂ = 2

\times

10^{$-$ 6}

so,

{{{S_{{A_2}X}}} \over {{S_{MX}}}} = {{{{10}^{ - 4}}} \over {2 \times {{10}^{ - 6}}}} = 50

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