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QJEEM21Ch5fe7: JEE Main 2021 Chemistry - Class 11 JEEM21Ch5fe7 Solution: 15 mL of aqueous solution of Fe 2+ in acidic medium completely…

15 mL of aqueous solution of Fe2+ in acidic medium completely reacted with 20 mL of 0.03 M aqueous Cr2O 72−_7^{2 - } . The molarity of the Fe2+ solution is __________ ×\times 10-2 M. (Round off to the Nearest Integer).

Step-by-Step Verified Solution

Cr2O72−+Fe2+⟶Cr3++Fe3+C{r_2}{O_7}^{2 - } + F{e^{2 + }}\mathrel{\mathop{\kern0pt\longrightarrow}\limits_{}} C{r^{3 + }} + F{e^{3 + }}

Valance Factor of Cr2O72−C{r_2}{O_7}^{2 - } = 6

Valance Factor of Fe2+F{e^{2 + }} = 1

mili eq. of Cr2O72−C{r_2}{O_7}^{2 - } = mili eq. of Fe2+

6(0.03 ×\times 20) = 1(M ×\times 15)

M = 6(0.03)4/3

M = 0.24 M

M = 24 ×\times 10 −- 2 M

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