QJEEM21Ch5d6d: JEE Main 2021 Chemistry - Class 11 JEEM21Ch5d6d Solution: Data given for the following reaction is as follows : FeO (s) + …

Question

Verified Solution • 2025–26 Session moderate

Data given for the following reaction is as follows :

FeO_(s) + C_(graphite)

\to

Fe_(s) + CO_(g)

The minimum temperature in K at which the reaction becomes spontaneous is ___________. (Integer answer)

Accepted Answer

{T_{\min }} = \left( {{{{\Delta ^0}H} \over {{\Delta ^0}S}}} \right)

{\Delta ^0}{H_{rxn}} = \left[ {\Delta _f^0H(Fe) + \Delta _f^0H(CO)} \right] -

= \left[ {\Delta _f^0H(FeO) + \Delta _f^0H({C_{(graphite)}})} \right]

= [0 - 110.5] - [ - 266.3 + 0]

= 155.8 kJ/mol

{\Delta ^0}{S_{rxn}} = \left[ {{\Delta ^0}S(Fe) + {\Delta ^0}S(CO)} \right] -

\left[ {{\Delta ^0}S(FeO) + {\Delta ^0}S({C_{(graphite)}})} \right]

= [27.28 + 197.6] - [57.49 + 5.74]

= 161.65 J/mol-K

{T_{\min }} = {{155.8 \times {{10}^3}J/mol} \over {161.65J/mol - K}} = 963.8

K

\simeq 964

k (nearest integer)

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