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QJEEM21Ch5a7f: JEE Main 2021 Chemistry - Class 11 JEEM21Ch5a7f Solution: In molecule, the hybridization of carbon 1, 2, 3 and 4…

In C1H2=C2=C3H−C4H3\mathop C\limits^1 {H_2} = \mathop C\limits^2 = \mathop C\limits^3 H - \mathop C\limits^4 {H_3} molecule, the hybridization of carbon 1, 2, 3 and 4 respectively, are :

Multiple Choice Options

  • A sp2, sp, sp2, sp3
  • B sp2, sp2, sp2, sp3
  • C sp3, sp, sp3, sp3
  • D sp2, sp3, sp2, sp3

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JEE Main 2021 (Online) 26th February Evening Shift Chemistry - Hydrocarbons Question 83 English Explanation

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