QJEEM21Ch5847: JEE Main 2021 Chemistry - Class 12 JEEM21Ch5847 Solution: For the reaction A B, the rate constant k(in s 1 ) is given by…

Question

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For the reaction A

\to

B, the rate constant k(in s^{$-$ 1}) is given by

{\log _{10}}k = 20.35 - {{(2.47 \times {{10}^3})} \over T}

The energy of activation in kJ mol^{$-$ 1} is ____________. (Nearest integer) [Given : R = 8.314 J K^{$-$ 1} mol^{$-$ 1}]

Accepted Answer

Given,

\log K = 20.35 - {{2.47 \times {{10}^3}} \over T}

We know

\log K = \log A - {{{E_a}} \over {2.303RT}}

\Rightarrow {{{E_a}} \over {2.303RT}} = 2.47 \times {10^3}

{E_a} = 2.47 \times {10^3} \times 2.303 \times {{8.314} \over {1000}}

KJ/mole

= 47.29 = 47 (Nearest integer)

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