QJEEM21Ch57d1: JEE Main 2021 Chemistry - Class 12 JEEM21Ch57d1 Solution: In the ground state of atomic Fe(Z = 26), the spin-only…

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In the ground state of atomic Fe(Z = 26), the spin-only magnetic moment is ____________

\times

10^{$-$ 1} BM. (Round off to the Nearest Integer). [Given :

\sqrt 3

= 1.73,

\sqrt 2

= 1.41 ]

Accepted Answer

{}_{26}Fe = [Ar]3{d^6}4{s^2}

No. of unpaired electrons = 4

\mu = \sqrt {n(n + 2)} BM

= \sqrt {4(4 + 2)} = \sqrt {24}

= 2\sqrt {3 \times 2} = 2[1.73 \times 1.41]

= 4.8786 BM

=

48.78 \times {10^{ - 1}}

BM

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