Verified Solution • 2025–26 Session moderate

QJEEM21Ch575f: JEE Main 2021 Chemistry - Class 12 JEEM21Ch575f Solution: A 5.0 m mol dm 3 aqueous solution of KCl has a conductance of…

A 5.0 m mol dm −- 3 aqueous solution of KCl has a conductance of 0.55 mS when measured in a cell of cell constant 1.3 cm −- 1. The molar conductivity of this solution is ___________ mSm2 mol −- 1. (Round off to the Nearest Integer).

Step-by-Step Verified Solution

Conductance = ConductivityCell constan⁡t{{Conductivity} \over {Cell\,cons\tan t}}

∴\therefore Conductivity = 0.55 ×\times 10 −- 3 ×\times 1.3 S cm −- 1

Molar conductivity = Conductivity (S cm−1)×1000Molarity (mol/L){{Conductivity\,(S\,c{m^{ - 1}}) \times 1000} \over {Molarity\,(mol/L)}}

=0.55×10−3×1.3×1005×10−3= {{0.55 \times {{10}^{ - 3}} \times 1.3 \times 100} \over {5 \times {{10}^{ - 3}}}}

= 143 S cm2 mol −- 1

= 14.3 mS m2 mol −- 1

≈\approx 14 mS m2 mol −- 1

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