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QJEEM21Ch4d75: JEE Main 2021 Chemistry - Class 12 JEEM21Ch4d75 Solution: In a binary compound, atoms of element A form a hcp structure…

In a binary compound, atoms of element A form a hcp structure and those of element M occupy 2/3 of the tetrahedral voids of the hcp structure. The formula of the binary compound is :

Multiple Choice Options

  • A M2A3
  • B M4A3
  • C M4A
  • D MA3

Step-by-Step Verified Solution

In HCP unit cell,

Z = 6 so A = 6

Also we know, in HCP

Tetrahedral voids = 2Z = 12

∴\therefore No. of M = 23{2 \over 3} [TV] = 23{2 \over 3} ×\times 12 = 8

∴\therefore Formula = M8A6 = M4A3

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