Verified Solution • 2025–26 Session moderate

QJEEM21Ch4992: JEE Main 2021 Chemistry - Class 11 JEEM21Ch4992 Solution: If 80 g of copper sulphate CuSO 4 . 5H 2 O is dissolved in…

If 80 g of copper sulphate CuSO4 . 5H2O is dissolved in deionised water to make 5L of solution. The concentration of the copper sulphate solution is x × 10−3 mol L−1. The value of x is _____________.

[Atomic masses Cu : 63.54u, S : 32u, O : 16u, H : 1u]

Step-by-Step Verified Solution

Given, mass of CuSO4 . 5H2O = 80 g

The concentration of copper sulphate solution is x × 10−3 mol/L.

Molarity = NumberofmolesofsoluteVolumeofsolution(L) ..... (i)

Molar mass of CuSO4 . 5H2O = 63.54 + 32 + 16 × 4

= 5 × 18 = 249.54 g/mol

Number of moles of solute = WeightofsoluteMolecularmassofsolute

= 80g249.54g/mol = 0.32 mol

Volume of solution = 5 L

From Eq. (i),

Molarity = 0.32055 = 64.11 × 10−3 mol/L

∴ x = 64.11

or x ≈ 64

Hence, answer is 64.

Related Learning Resources & Exam Preparation