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QJEEM21Ch490a: JEE Main 2021 Chemistry - Class 12 JEEM21Ch490a Solution: [Ti(H 2 O) 6 ] 3+ absorbs light of wavelength 498 nm during a d …

[Ti(H2O)6]3+ absorbs light of wavelength 498 nm during a d −- d transition. The octahedral splitting energy for the above complex is ____________ ×\times 10 −- 19 J. (Round off to the Nearest Integer). h = 6.626 ×\times 10 −- 34 Js; c = 3 ×\times 108 ms −- 1

Step-by-Step Verified Solution

Octahedral splitting energy = hcλ{{hc} \over \lambda }

=6.626×10−34×3×108498×10−9= {{6.626 \times {{10}^{ - 34}} \times 3 \times {{10}^8}} \over {498 \times {{10}^{ - 9}}}}

=3.99×10−19J= 3.99 \times {10^{ - 19}}J

≈4×10−19\approx 4 \times {10^{ - 19}}

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