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QJEEM21Ch3c8e: JEE Main 2021 Chemistry - Class 11 JEEM21Ch3c8e Solution: Identify the elements X and Y using the ionisation energy…
Identify the elements X and Y using the ionisation energy values given below :
| Ionization energy (kJ/mol) | ||
|---|---|---|
| 1 | 2 | |
| X | 495 | 4563 |
| Y | 731 | 1450 |
Multiple Choice Options
- A X = F; Y = Mg
- B X = Mg; Y = F
- C X = Na; Y = Mg
- D X = Mg; Y = Na
Step-by-Step Verified Solution
Due to 2p6, noble gas electronic configuration, the second ionisation enthalpy of Na is very high. That’s why has large difference between IE1, and IE2
Mg+ is 2p6, 3s1.
After the loss of one electron, Mg+ will be formed with noble gas electronic configuration. That’s why has less difference between I.E1 and I.E2, but it's I.E3 is very high.
Mg+ is 2p6, 3s1.
After the loss of one electron, Mg+ will be formed with noble gas electronic configuration. That’s why has less difference between I.E1 and I.E2, but it's I.E3 is very high.