Verified Solution • 2025–26 Session moderate

QJEEM21Ch333a: JEE Main 2021 Chemistry - Class 12 JEEM21Ch333a Solution: Given below are two statements : Statement I : The limiting…

Given below are two statements :

Statement I : The limiting molar conductivity of KCl (strong electrolyte) is higher compared to that of CH3COOH (weak electrolyte).

Statement II : Molar conductivity decreases with decrease in concentration of electrolyte.

In the light of the above statements, choose the most appropriate answer from the options given below :

Multiple Choice Options

  • A Statement I is true but Statement II is false.
  • B Statement I is false but Statement II is true.
  • C Both Statement I and Statement II are true.
  • D Both Statement I and Statement II are false.

Step-by-Step Verified Solution

Ion H+{H^ + } K+{K^ + } Cl−C{l^ - } CH3COO−C{H_3}CO{O^ - }
Λm Scm2/mole∞\Lambda _{m\,Sc{m^2}/mole}^\infty 349.8 73.5 76.3 40.9


So,

Λm  CH3COOH∞=Λm  (H+)∞+Λm  CH3COO−∞\Lambda _{m\,\,C{H_3}COOH}^\infty = \Lambda _{m\,\,({H^ + })}^\infty + \Lambda _{m\,\,C{H_3}CO{O^ - }}^\infty

= 349.8 + 40.9 = 390.7 Scm2/mole

Λm  KCl∞=Λm  (K+)∞+Λm  (Cl−)∞\Lambda _{m\,\,KCl}^\infty = \Lambda _{m\,\,({K^ + })}^\infty + \Lambda _{m\,\,(C{l^ - })}^\infty

= 73.5 + 76.3 = 149.3 Scm2/mole

So, Statement I is wrong or false.

As the concentration decreases, the dilution increases which increases the degree of dissociation, thus increasing the no. of ions, which increases the molar conductance.

So Statement II is false.

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