QJEEM21Ch21cf: JEE Main 2021 Chemistry - Class 12 JEEM21Ch21cf Solution: For a certain first order reaction 32% of the reactant is left…

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For a certain first order reaction 32% of the reactant is left after 570s. The rate constant of this reaction is _________

\times

10^{$-$ 3} s^{$-$ 1}. (Round off to the Nearest Integer). [Given : log₁₀2 = 0.301, ln10 = 2.303]

Accepted Answer

k = {1 \over t}\ln \left[ {{a \over {a - x}}} \right]

k = {{2.303} \over {570}}\log \left( {{{100} \over {32}}} \right)

k = {{2.303} \over {570}}\left[ {\log ({{10}^2}) - \log {2^5}} \right]

k = {{2.303} \over {570}} \times 0.5

k = 2 \times {10^{ - 3}}{s^{ - 1}}

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