Verified Solution • 2025–26 Session moderate

QJEEM21Ch15cf: JEE Main 2021 Chemistry - Class 12 JEEM21Ch15cf Solution: Assume a cell with the following reaction V E cell for the…

Assume a cell with the following reaction

Cu(s)+2Ag+(1×10−3M)→Cu2+(0.250M)+2Ag(s)C{u_{(s)}} + 2A{g^ + }(1 \times {10^{ - 3}}M) \to C{u^{2 + }}(0.250M) + 2A{g_{(s)}}

EcellΘ=2.97E_{cell}^\Theta = 2.97 V

Ecell for the above reaction is ______________ V. (Nearest integer)

[Given : log 2.5 = 0.3979, T = 298 K]

Step-by-Step Verified Solution

E=Eo−0.0592log⁡[Cu+2][Ag+]2E = {E^o} - {{0.059} \over 2}\log {{[C{u^{ + 2}}]} \over {{{[A{g^ + }]}^2}}}

=2.97−0.0592log⁡0.25(10−3)2=2.81V= 2.97 - {{0.059} \over 2}\log {{0.25} \over {{{({{10}^{ - 3}})}^2}}} = 2.81V

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