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QJEEM21Ch1597: JEE Main 2021 Chemistry - Class 12 JEEM21Ch1597 Solution: CO 2 gas is bubbled through water during a soft drink…

CO2 gas is bubbled through water during a soft drink manufacturing process at 298 K. If CO2 exerts a partial pressure of 0.835 bar then x m mol of CO2 would dissolve in 0.9 L of water. The value of x is ____________. (Nearest integer)

(Henry's law constant for CO2 at 298 K is 1.67 ×\times 103 bar)

Step-by-Step Verified Solution

From Henry's law

Pgas = KH.Xgas

0.835 = 1.67 ×\times 103 ×\times n(CO2)0.9×100018{{n(C{O_2})} \over {{{0.9 \times 1000} \over {18}}}}

⇒\Rightarrow n(CO2) = 0.025

Millimoles of CO2 = 0.025 ×\times 1000 = 25

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