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QJEEM21Ch11a9: JEE Main 2021 Chemistry - Class 12 JEEM21Ch11a9 Solution: Number of electrons present in 4f orbital of Ho 3+ ion is…
Number of electrons present in 4f orbital of Ho3+ ion is ____________. (Given Atomic No. of Ho = 67)
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Ho = [Xe]4f116s2
Ho3+ = [Xe] 4f10
So number of e present in 4f is 10.
Ho3+ = [Xe] 4f10
So number of e