Verified Solution • 2025–26 Session moderate

QJEEM21Ch1061: JEE Main 2021 Chemistry - Class 12 JEEM21Ch1061 Solution: 'A' and 'B' in the following reactions are :

'A' and 'B' in the following reactions are :

JEE Main 2021 (Online) 24th February Morning Shift Chemistry - Compounds Containing Nitrogen Question 152 English

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/89c4ceb6cb48020a50ec348651ce2d9cc13303379c5cc050b067ecd296679d57.webp
  • B https://ik.imagekit.io/novatra/photos/b977f896cb34b5d3d1493105b701a782dffc838cf40550a6a69ee40ba7cca7ee.webp
  • C https://ik.imagekit.io/novatra/photos/af75dbafdccbc91ae34bffa53afaf1ba54ae9dc091b4b867c7e874140164dcaa.webp
  • D https://ik.imagekit.io/novatra/photos/f0d7977cdbf8d03a6385e1dfaa4a904ae274f17da1b5417530b79b4d6f559355.webp

Step-by-Step Verified Solution

Step 1 : In step 1, NaNO2 + HCl , 0-5°C used for diazotisation reaction. It will form diazonium salt. Further, it will react with KCN to form cyanobenzene.

JEE Main 2021 (Online) 24th February Morning Shift Chemistry - Compounds Containing Nitrogen Question 152 English Explanation 1
Step 2 : In step 2, SnCl2 and HCl is a Stephen’s reduction reagent. Cyanobenzene reduced to benzaldehyde by SnCl2/HCl.

JEE Main 2021 (Online) 24th February Morning Shift Chemistry - Compounds Containing Nitrogen Question 152 English Explanation 2

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