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QJEEM21Ch0fac: JEE Main 2021 Chemistry - Class 11 JEEM21Ch0fac Solution: Assuming that Ba(OH) 2 is completely ionised in aqueous…

Assuming that Ba(OH)2 is completely ionised in aqueous solution under the given conditions the concentration of H3O+ ions in 0.005 M aqueous solution of Ba(OH)2 at 298 K is ______________ ×\times 10 −- 12 mol L −- 1. (Nearest integer)

Step-by-Step Verified Solution

Ba(OH)2→Ba+2+2OH−↓2×0.005=0.01=10−2Ba{(OH)_2} \to B{a^{ + 2}} + 2O{H^ - } \downarrow 2 \times 0.005 = 0.01 = {10^{ - 2}}

At 298 K : in aq. solution [H3O+][OH−]=10−14[{H_3}{O^ + }][O{H^ - }] = {10^{ - 14}}

[H3O+]=10−1410−2=10−12[{H_3}{O^ + }] = {{{{10}^{ - 14}}} \over {{{10}^{ - 2}}}} = {10^{ - 12}}

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