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QJEEM21Ch0f3e: JEE Main 2021 Chemistry - Class 11 JEEM21Ch0f3e Solution: An organic compound is subjected to chlorination to get…

An organic compound is subjected to chlorination to get compound A using 5.0 g of chlorine. When 0.5 g of compound A is reacted with AgNO3 [Carius Method], the percentage of chlorine in compound A is ____________ when it forms 0.3849 g of AgCl. (Round off to the Nearest Integer)

(Atomic masses of Ag and Cl are 107.87 and 35.5 respectively)

Step-by-Step Verified Solution

Mass of organic compound = 0.5 gm.

Mass of formed AgCl = 0.3849 gm

% of Cl = atomic mass of Cl×mass formed AgClmolecular mass of AgCl×mass of organic compound×100{{atomic\,mass\,of\,Cl \times mass\,formed\,AgCl} \over {molecular\,mass\,of\,AgCl \times mass\,of\,organic\,compound}} \times 100

=35.5×0.3849143.37×0.5×100= {{35.5 \times 0.3849} \over {143.37 \times 0.5}} \times 100

= 19.06

≈\approx 19

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