Verified Solution • 2025–26 Session
moderate
QJEEM21Ch0dd1: JEE Main 2021 Chemistry - Class 12 JEEM21Ch0dd1 Solution: Match List - I with List - II. List - I List - II (a) Sodium…
Match List - I with List - II.
Choose the correct answer from the options given below :
| List - I | List - II | ||
|---|---|---|---|
| (a) | Sodium Carbonate | (i) | Deacon |
| (b) | Titanium | (ii) | Castner-Kellner |
| (c) | Chlorine | (iii) | van-Arkel |
| (d) | Sodium hydroxide | (iv) | Solvay |
Choose the correct answer from the options given below :
Multiple Choice Options
- A (a) (iv), (b) (iii), (c) (i), (d) (ii)
- B (a) (iv), (b) (i), (c) (ii), (d) (iii)
- C (a) (iii), (b) (ii), (c) (i), (d) (iv)
- D (a) (i), (b) (iii), (c) (iv), (d) (ii)
Step-by-Step Verified Solution
(a) Sodium carbonate is prepared by Solvay process
(b) Titanium is refined by Van-Arkel process
(c) Chlorine is prepared by Deacon process
(d) Sodium hydroxide is prepared by Castner-Kellner process
(b) Titanium is refined by Van-Arkel process
(c) Chlorine is prepared by Deacon process
(d) Sodium hydroxide is prepared by Castner-Kellner process