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QJEEM21Ch0d1f: JEE Main 2021 Chemistry - Class 11 JEEM21Ch0d1f Solution: The pH of a solution obtained by mixing 50 mL of 1 M HCl and 30 …

The pH of a solution obtained by mixing 50 mL of 1 M HCl and 30 mL of 1 M NaOH is x ×\times 10 −- 4. The value of x is ____________. (Nearest integer) [log 2.5 = 0.3979]

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JEE Main 2021 (Online) 31st August Evening Shift Chemistry - Ionic Equilibrium Question 51 English Explanation

[HCl]=2080=14M=2.5×10−1M[HCl] = {{20} \over {80}} = {1 \over 4}M = 2.5 \times {10^{ - 1}}M

pH = −- log 2.15 ×\times 10-1 = 1 −- 0.3979 = 0.6021

pH = 6021 ×\times 10-4

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