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QJEEM21Ch0bf1: JEE Main 2021 Chemistry - Class 11 JEEM21Ch0bf1 Solution: Dichromate ion is treated with base, the oxidation number of Cr …

Dichromate ion is treated with base, the oxidation number of Cr in the product formed is ___________.

Step-by-Step Verified Solution

Cr2O72−+2OH−C{r_2}O_7^{2 - } + 2O{H^ - } ⇌ 2CrO42−+H2O2CrO_4^{2 - } + {H_2}O

Let Oxidation state of Cr in CrO42−CrO_4^{2 - } is = x.

∴\therefore x + (–2 × 4) = –2

⇒\Rightarrow x = 6

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