QJEEM21Ch070d: JEE Main 2021 Chemistry - Class 11 JEEM21Ch070d Solution: 1.86 g of aniline completely reacts to form acetanilide. 10% of …

Given, weight = 18.6 g

Here, 1 mole of aniline gives 1 mole of acetanilide

$\therefore$ mole of aniline = mole of acetanilide

$\Rightarrow$ ${{1.86} \over {93}} = {{{W_\text{Acetanilide}}} \over {135}}$

${W_\text{Acetanilide}} = {{1.86 \times 135} \over {93}}g = 2.70g$

But efficiency of reaction is 90% only.

Hence, mass of acetanilide produced $= 2.70 \times {{90} \over {100}}g = 2.43g = 243 \times {10^2}g$

x = 243