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QJEEM21Ch04fd: JEE Main 2021 Chemistry - Class 11 JEEM21Ch04fd Solution: When 5.1 g of solid NH 4 HS is introduced into a two litre…

When 5.1 g of solid NH4HS is introduced into a two litre evacuated flask at 27 ∘^\circ C, 20% of the solid decomposes into gaseous ammonia and hydrogen sulphide. The Kp for the reaction at 27 ∘^\circ C is x ×\times 10 −- 2. The value of x is _____________. (Integer answer) [Given R = 0.082 L atm K −- 1 mol −- ]

Step-by-Step Verified Solution

moles of NH4HS initially taken = 5.1g51g/mol{{5.1g} \over {51g/mol}} = 0.1 mol

volume of vessel = 2 litre

JEE Main 2021 (Online) 27th August Evening Shift Chemistry - Chemical Equilibrium Question 41 English Explanation

⇒\Rightarrow partial pressure of each component

P=nRTV=0.1×0.2×0.082×3002P = {{nRT} \over V} = {{0.1 \times 0.2 \times 0.082 \times 300} \over 2}

= 0.246 atm

⇒\Rightarrow kP = P NH3N{H_3} ×\times P H2S{H_2}S = (0.246)2 = 0.060516

= 6.05 ×\times 10 −- 2

∴\therefore x = 6

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