Verified Solution • 2025–26 Session
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QJEEM21Ch02e9: JEE Main 2021 Chemistry - Class 12 JEEM21Ch02e9 Solution: Cu 2+ salt reacts with potassium iodide to give
Cu2+ salt reacts with potassium iodide to give
Multiple Choice Options
- A Cu2I2
- B Cu2I3
- C Cul
- D Cu(I3)2
Step-by-Step Verified Solution
When a copper(II) salt (containing Cu²⁺) is treated with potassium iodide (KI), the cupric ions (Cu²⁺) are reduced to copper(I) (Cu⁺), and iodine (I₂) is released. The solid product formed in the reaction is copper(I) iodide, CuI.
The simplified reaction is:
So, the correct answer is:
Option C: CuI.