Verified Solution • 2025–26 Session moderate

QJEEM20Phfa66: JEE Main 2020 Physics - Class 11 JEEM20Phfa66 Solution: If momentum (P), area (A) and time (T) are taken to be the…

If momentum (P), area (A) and time (T) are taken to be the fundamental quantities then the dimensional formula for energy is

Multiple Choice Options

  • A [P2AT–2]
  • B [P12AT−1]\left[ {{P^{{1 \over 2}}}A{T^{ - 1}}} \right]
  • C [PA12T−1]\left[ {P{A^{{1 \over 2}}}{T^{ - 1}}} \right]
  • D [PA–1T–2]

Step-by-Step Verified Solution

Let [E] = K[P]x[A]y [T]z

[ML2T–2] = [MLT–1]x[L2]y[T]z

[ML2T–2] = [Mx][Lx+2y][T–x+z]

Comparing both side we get,

x = 1

x + 2y = 2

⇒\Rightarrow 1 + 2y= 2 or y = 12\frac{1}{2}

z – x = –2 ⇒\Rightarrow z–1 = –2 or z = –1

∴\therefore [E] = [PA12T−1]\left[ {P{A^{{1 \over 2}}}{T^{ - 1}}} \right]

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