Verified Solution • 2025–26 Session moderate

QJEEM20Phf05e: JEE Main 2020 Physics - Class 11 JEEM20Phf05e Solution: A body of mass m = 10 kg is attached to one end of a wire of…

A body of mass m = 10 kg is attached to one end of a wire of length 0.3 m. The maximum angular speed (in rad s–1) with which it can be rotated about its other end in space station is :
(Breaking stress of wire = 4.8 × 107 Nm–2 and
area of cross-section of the wire = 10–2 cm2) is:

Step-by-Step Verified Solution

T = m ω2l{\omega ^2}l

Breaking stress = σ\sigma = mω2lA{{m{\omega ^2}l} \over A}

⇒\Rightarrow ω2{\omega ^2} = 4.8×107×(10−2×10−4)10×0.3{{4.8 \times {{10}^7} \times \left( {{{10}^{ - 2}} \times {{10}^{ - 4}}} \right)} \over {10 \times 0.3}} = 16

⇒\Rightarrow ω\omega = 4

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring