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QJEEM20Phea13: JEE Main 2020 Physics - Class 12 JEEM20Phea13 Solution: In the circuit shown in the figure, the total charge is 750 μ C …

In the circuit shown in the figure, the total charge is 750 μC and the voltage across capacitor C2 is 20 V. Then the charge on capacitor C2 is : JEE Main 2020 (Online) 3rd September Morning Slot Physics - Capacitor Question 98 English

Multiple Choice Options

  • A 160 μC
  • B 450 μC
  • C 590 μC
  • D 650 μC

Step-by-Step Verified Solution

JEE Main 2020 (Online) 3rd September Morning Slot Physics - Capacitor Question 98 English Explanation

Q2 = CV = 8 × 20 = 160 μC

Q1 = 750 - 160 = 590 μC

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