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QJEEM20Phe433: JEE Main 2020 Physics - Class 11 JEEM20Phe433 Solution: As shown in figure, when a spherical cavity (centered at O) of…

As shown in figure, when a spherical cavity (centered at O) of radius 1 is cut out of a uniform sphere of radius R (centered at C), the centre of mass of remaining (shaded) part of sphere is at G, i.e, on the surface of the cavity. R can be detemined by the equation : JEE Main 2020 (Online) 8th January Evening Slot Physics - Center of Mass and Collision Question 78 English

Multiple Choice Options

  • A (R2 + R – 1) (2 – R) = 1
  • B (R2 – R – 1) (2 – R) = 1
  • C (R2 – R + 1) (2 – R) = 1
  • D (R2 + R + 1) (2 – R) = 1

Step-by-Step Verified Solution

JEE Main 2020 (Online) 8th January Evening Slot Physics - Center of Mass and Collision Question 78 English Explanation
By concept of COM

m0R0 = mcavityRcavity

⇒ (43πR3ρ−43π(1)3ρ) (2 - R) = 43π(1)3ρ × (R - 1)

⇒ (R3 – 1) (2 – R) = R – 1

⇒(R2 + R + 1) (2 – R) = 1

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