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QJEEM20Phe39e: JEE Main 2020 Physics - Class 11 JEEM20Phe39e Solution: Consider a gas of triatomic molecules. The molecules are…

JEE Main 2020 (Online) 3rd September Morning Slot Physics - Heat and Thermodynamics Question 273 English Consider a gas of triatomic molecules. The molecules are assumed to be triangular and made of massless rigid rods whose vertices are occupied by atoms. The internal energy of a mole of the gas at temperature T is :

Multiple Choice Options

  • A 32RT{3 \over 2}RT
  • B 92RT{9 \over 2}RT
  • C 52RT{5 \over 2}RT
  • D 3RT

Step-by-Step Verified Solution

Degree of freedom (f) = 3 + 3 = 6 and n = 1

U = f2nRT{f \over 2}nRT

= 62×1×RT{6 \over 2} \times 1 \times RT

= 3RT

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